{"id":4558,"date":"2015-03-29T11:23:39","date_gmt":"2015-03-29T09:23:39","guid":{"rendered":"https:\/\/kamerpower.com\/?p=4558"},"modified":"2025-06-19T00:12:21","modified_gmt":"2025-06-18T23:12:21","slug":"concours-eamac-2011-epreuve-de-physique-ing-cca","status":"publish","type":"post","link":"https:\/\/kamerpower.com\/fr\/concours-eamac-2011-epreuve-de-physique-ing-cca\/","title":{"rendered":"Epreuve de Concours EAMAC 2011 Physique ING &#038; CCA"},"content":{"rendered":"<p style=\"text-align: center;\"><span style=\"color: #000000;\">CONCOURS D\u2019ENTREE AUX CYCLES D\u2019INGENIEUR ET DE<\/span><br \/>\n<span style=\"color: #000000;\">CONTROLEUR DE LA CIRCULATION AERIENNE DE L\u2019ECOLE<\/span><br \/>\n<span style=\"color: #000000;\">AFRICAINE DE LA METEOROLOGIE ET<\/span><br \/>\n<span style=\"color: #000000;\">DE L\u2019AVIATION CIVILE ( EAMAC )<\/span><br \/>\n<span style=\"color: #000000;\">SESSION 2011\u00a0Concours EAMAC.<\/span><br \/>\n<strong><span style=\"color: #000000;\">EPREUVE DE : <span style=\"color: #3366ff;\">PHYSIQUE<\/span><\/span><\/strong><br \/>\n<span style=\"color: #000000;\">DUREE : 3\u00a0HEURES\u00a0<\/span><br \/>\n<span style=\"color: #008000; text-shadow: 2px 0 2px #000;\">KA<\/span><span style=\"color: #ff0000; text-shadow: 2px 0 2px #000;\">M<\/span><span style=\"color: #ffcc00; text-shadow: 2px 0 2px #000;\">ER<\/span><span style=\"color: #800080; text-shadow: 2px 0 2px #000;\">POWER<\/span><span style=\"color: #3366ff; text-shadow: 2px 0 2px #000;\">.COM<\/span><\/p>\n<hr \/>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_82_2 counter-hierarchy ez-toc-counter ez-toc-custom ez-toc-container-direction\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Contents<\/p>\n<label for=\"ez-toc-cssicon-toggle-item-69de1d3d02b8d\" class=\"ez-toc-cssicon-toggle-label\"><span class=\"ez-toc-cssicon\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/label><input type=\"checkbox\"  id=\"ez-toc-cssicon-toggle-item-69de1d3d02b8d\"  aria-label=\"Toggle\" \/><nav><ul class='ez-toc-list ez-toc-list-level-1 ' ><ul class='ez-toc-list-level-4' ><li class='ez-toc-heading-level-4'><ul class='ez-toc-list-level-4' ><li class='ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/kamerpower.com\/fr\/concours-eamac-2011-epreuve-de-physique-ing-cca\/#telechargez-les-anciens-epreuves-dexamen-eamac-2006-a-2025-et-les-corrigees-depuis-notre-application-kamerpower-epreuves-sur-play-store\" >T\u00e9l\u00e9chargez les anciens \u00e9preuves d&#8217;examen EAMAC 2006 \u00e0 2025\u00a0et les Corrig\u00e9es depuis notre application Kamerpower Epreuves sur Play Store.<\/a><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/kamerpower.com\/fr\/concours-eamac-2011-epreuve-de-physique-ing-cca\/#epreuve-de-concours-eamac-2011-physique-ing-cca\" >Epreuve de Concours EAMAC 2011 Physique ING &amp; CCA<\/a><ul class='ez-toc-list-level-3' ><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/kamerpower.com\/fr\/concours-eamac-2011-epreuve-de-physique-ing-cca\/#exercice-1\" >Exercice 1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/kamerpower.com\/fr\/concours-eamac-2011-epreuve-de-physique-ing-cca\/#exercice-2\" >Exercice 2<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h4 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"telechargez-les-anciens-epreuves-dexamen-eamac-2006-a-2025-et-les-corrigees-depuis-notre-application-kamerpower-epreuves-sur-play-store\"><\/span><span style=\"color: #000000;\"><strong><span style=\"color: #008000;\">T\u00e9l\u00e9chargez<\/span> les anciens <span style=\"color: #008000;\">\u00e9preuves d&#8217;examen EAMAC 2006 \u00e0 2025<\/span>\u00a0et les <span style=\"color: #008000;\">Corrig\u00e9es<\/span> depuis notre application Kamerpower Epreuves sur Play Store.<\/strong><\/span><span class=\"ez-toc-section-end\"><\/span><\/h4>\n<p><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=com.kamerpower.cm\" target=\"_blank\" rel=\"noopener\"><img decoding=\"async\" class=\"aligncenter wp-image-68899\" src=\"https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr.png\" alt=\"Kamerpower Epreuves\" width=\"393\" height=\"152\" srcset=\"https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr.png 646w, https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr-600x232.png 600w, https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr-300x116.png 300w, https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr-520x201.png 520w, https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr-320x124.png 320w, https:\/\/kamerpower.com\/wp-content\/uploads\/2025\/05\/google-play-badge-fr-150x58.png 150w\" sizes=\"(max-width: 393px) 100vw, 393px\" \/><\/a><\/p>\n<hr \/>\n<h2 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"epreuve-de-concours-eamac-2011-physique-ing-cca\"><\/span><span style=\"color: #3366ff;\">Epreuve de Concours EAMAC 2011 Physique ING &amp; CCA<\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"exercice-1\"><\/span><span style=\"color: #ff0000;\">Exercice 1<\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">On considere l\u2019unit\u00e9 de masse de gaz parfait. On rappelle que dans une transformation\u00a0reversible d\u2019un fluide, la quantit\u00e9 de chaleur mise en jeu dQ (c&#8217;eStia-dire \u00e9chang\u00e9e avec le\u00a0milieu ext\u00e9rieur) s\u2019\u00e9crit sous les formes:<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">dQ=C_{{V}}dT +l dV lorsque la temperature varie de dT et le volume de dV.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">dQ=C_{{P}}dT +h dP lorsque la temperature varie de dT et la pression de dP.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">1)<\/span> Ecrire les expressions des diff\u00e9rentielles de l\u2019\u00e9nergie inteme dU, de l\u2019enthalpie dH et\u00a0de l\u2019entropie dS. En d\u00e9duire les relations:<\/span><\/p>\n<p>l = &#8211; T (dP\/dT)v, h = -T (dV\/dT)p, Cp &#8211; Cv = T(dP\/dT)v(dv\/dT)p<\/p>\n<p><span style=\"color: #000000;\">2) On considere l\u2019unit\u00e9 de masse de gaz r\u00e9el qui ob\u00e9it a l\u2019\u00e9quation de Van der Waals:<\/span><\/p>\n<p>(P + a\/v^2) (V &#8211; b) = rT<\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">a) Etablir les expressions des coefficients I\u00a0et h.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">b) Etablir l\u2019expression du travail re\u00e7u par le gaz, au cours d\u2019une compression isotherme\u00a0<\/span><span style=\"color: #000000;\">reversible s\u2019effectuant entre les volumes\u00a0V_{{1}}\u00a0\u00a0et\u00a0V_{{2}},\u00a0\u00e0 la temp\u00e9rature\u00a0T.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">3)<\/span> Que devient l\u2019expression de ce travail, aux basses pressions (b&lt;&lt;V) ?<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">4)<\/span> a) D\u00e9terminer la difference des chaleurs sp\u00e9cifiques\u00a0C_{{P}}-C_{{V}}\u00a0du gaz, en fonction\u00a0<\/span><span style=\"color: #000000;\">des variables ind\u00e9pendantes P, V \u00a0et des constantes a, b et r.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">b) En tenant compte du fait que a\/v^2 &lt; &lt; P \u00a0\u00a0\u00a0et \u00a0<em>b &lt;&lt; V<\/em>, trouver une formule approch\u00e9e de\u00a0C_{{P}}-C_{{V}}<\/span><span style=\"color: #000000;\">\u00a0\u00a0en fonction des variables P et T.<\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"exercice-2\"><\/span><span style=\"color: #ff0000;\">Exercice 2<\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><span style=\"color: #000000;\">Un point materiel M, de masse m, rep\u00e9r\u00e9 par ses coordonn\u00e9es polaires\u00a0( r, \\theta )\u00a0, est soumis a la\u00a0force Newtonienne : F = -(k\/r2)er<\/span><\/p>\n<p><span style=\"color: #000000;\">\u00a0\u00a0\u00a0avec (OM = r = re) \u00a0 \u00a0, de la part d\u2019un point O. k est une\u00a0est une\u00a0constante positive.<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">1)<\/span> Montrer que l\u2019\u00e9quation de la trajectoire de M peut \u00e9tre mise sous la forme:<\/span><\/p>\n<p><span style=\"color: #000000;\">o\u00f9 \u00a0\u00a0 est l\u2019axe focal a l\u2019origine, p 1e parametre de la conique et e son excentricit\u00e9.<\/span><br \/>\n<span style=\"color: #000000;\">Donner les expressions de p et e.<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">2)<\/span> On choisira la solution correspondant \u00e0 Uo = 0. Calculer l\u2019\u00e9nergie potentielle\u00a0E_{{P}}\u00a0de M\u00a0<\/span><span style=\"color: #000000;\">en fonction de k, p,\u00a0\\theta\u00a0et e. (On prendra l\u2019origine des potentiels \u00e0\u00a0l\u2019infini).<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">3)<\/span> Calculer l\u2019\u00e9nergie cin\u00e9tique\u00a0E_{{c}}\u00a0de M en fonction de k, p\u00a0\\theta\u00a0\u00a0et e.<\/span><\/p>\n<p><span style=\"color: #000000;\"><span style=\"color: #3366ff;\">4)<\/span> Calculer l\u2019e&#8217;nergie m\u00e9canique E de M. Montrer que E est constante.<\/span><br \/>\n<span style=\"color: #000000;\">On rappelle les formules de BINET<\/span><\/p>\n<p>p = 1\/r<\/p>\n<p style=\"text-align: center;\"><span style=\"color: #3366ff;\"><a style=\"color: #3366ff;\" href=\"https:\/\/kamerpower.com\/fr\/annales-des-epreuves-du-concours-eamac-asecna-2006-a-2018-epreuves\/\" rel=\"noopener\">Epreuve de Concours EAMAC 2011 Physique ING &amp; CCA<\/a><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":4530,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_themeisle_gutenberg_block_has_review":false,"footnotes":""},"categories":[1701],"tags":[1738,1735,1712,1726],"class_list":["post-4558","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-epreuves","tag-annales-epreuves-concours-eamac","tag-concours-eamac-ecole-africaine-de-la-meteorologie-et-de-laviation-civile","tag-epreuve-de-concours-dentree-aux-grandes-ecoles-cameroun","tag-physique"],"_links":{"self":[{"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/posts\/4558","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/comments?post=4558"}],"version-history":[{"count":2,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/posts\/4558\/revisions"}],"predecessor-version":[{"id":69934,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/posts\/4558\/revisions\/69934"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/media\/4530"}],"wp:attachment":[{"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/media?parent=4558"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/categories?post=4558"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kamerpower.com\/fr\/wp-json\/wp\/v2\/tags?post=4558"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}